What least number must be added to 1056 to get a number excatly divisible by 87
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75 should be added bcoz if we divide 1056by 87 so in 12 times we get perfect then we had reminder 12
so if we minus 12 from 87 ,we will get 75
so if we minus 12 from 87 ,we will get 75
Answered by
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75 added to 1056 then 1056+75=1131
which is divisible by 87 in 13 times
which is divisible by 87 in 13 times
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