Question

what least number must be added to 1056 to get a number exactly divisible by 23 ?​

Answer 1

Answer:

2 is the answer

Step-by-step explanation:

On replacing values given in the question in equation 1 we get

When we divide 1056 with 23, we get 21 as a remainder.

So, 23−21=2

So, 2 must be added to 1056 in order to make the sum completely divisible by 23.

∴ 1056+2=1058

Now, we can see that when 1058 is divided by 23 we get 46 as quotient and 0 as remainder.

∴ The least number that should be added to 1056, so that the sum is completely divisible by 23 is 2.