Question

what least number must be added to 1056 to get a number exactly divisible by 24 ?​

Answer 1

So, 23-21 = 2 must be added to 1056 in order to make sum completely divisible by 23. this means that when 1056 is divided by 23 it gives 21 as remainder, now if we add 2 in 21 it will become 23 and will become divisible by 23, therefore answer is 2.

Answer 2

no. = remainder of 1056/24
=44..rem=0

so 1056 is already divisible.

least no. is either 0 or 24