what least number must be added to 10560 to get a number exactly divisible by 23
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0
Answer:
2
Step-by-step explanation:
⇒ When 1056÷23, we get 21 as a remainder.
⇒ So, 23−21=2 must be added to 1056 in order to sum completely divisible by 23.
∴ 1056+2=1058
∴ The least number should be added to 1056, so that the sum is completely divisible by 23 is 2.
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3
Answer:
2
Step-by-step explanation:
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