What least number must be added to both the sides of the equation 4x^2+12x+7=0 to solve it by the method of completing the squares?
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Answer:
2
Step-by-step explanation:
4x2−12x+7
=(2x)2−2∗2x∗3+7
(a+b)2=a2+2∗a∗b+b2
Here , a=2x,b=−3
=(2x)2+2∗2x∗(−3)+32
=4x2−12x+9
=> We have to add 2 to make perfect square
vasantinikam2004:
Your answer is wrong
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