Question

What least number must be added to each of numbers 6,15,20,43 so that the resulting numbers are prop

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Let the number added be x.

∴ (6 + x) : (15 + x) :: (20 + x) (43 + x)

⇒6+x15+x=20+x43+x

⇒ (6 + x)(43 + x) (20 + x)(15 + x)

⇒258+6x+43x+x2=300+20x+15x+x2

⇒49x-35x=300-258

⇒14x=42

⇒x=3

Thus, the required number which should be added is 3.

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7 Ratio and Proportion (Including Properties and Uses) [Exercise 7 (B)] - Selina Concise Maths Class 10 ICSE

Q 6