What least number must be subtracted from 433026 to get a perfect square?
Answers
Question :- What least number must be subtracted from 433026 to get a perfect square ?
Solution :-
To find the number first we have to find the Perfect square near to 433026 .
Lets Try to solve with some trick :-
→ Last two digits have 6 in Last = So, if it is a perfect Square , than we have 4 or 6 in Last . (4² = 16, 6² = 36).
Now,
→ Remaining digits are = 4330
So,
→ upto 4330 we can go to Square of = 65 that is 4225 .
Than,
→ 433026 will either perfect square of 654 or 656 .
So,
→ (654)² = 427716
→ (656)² = 430336
Therefore, we can say that,
→ Square of 656 is the Nearest Perfect Square Number . {As (657)² > 430336.}
Hence,
→ Least number must be subtracted from 433026 to get a perfect square = 433026 - 430336 = 2690 .(Ans.)
{ Note :- Also the Perfect square number is square of 256.}
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