Question

what least number should be subtracted from the largest number of 5 digits so that the remaining number is exactly divisible by the largest number of 2 digit

Answer 1

Answer:

The least number that should be subtracted from the largest number of 5 digits(99999) so that the remaining number is exactly divisible by the largest number of 2 digit(99) is 9.

Step-by-step explanation:

• Largest number of 5 digit is 99999 .

• Largest number of 2 digit is 99.

• If largest 5-digit number 99999 will be divided by largest two digit number 99, then we will get 99999÷99=1010 with  Remainder=9.
• By subtracting the remainder 9 from the largest 5-digit number 99999, we will get 99999-9 = 99990.
• Hence, 99990 is the largest five digit number which is exactly divisible by the largest number of 2 digit 99.

• So, we can conclude that , the least number should be subtracted from the largest number of 5 digits(99999) so that the remaining number is exactly divisible by the largest number of 2 digit(99) is 9.

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