what least value which should be added to 1812 to make it divisible by 7 11 and 14
Answers
Answered by
11
The LCM of 7, 11 and 14 = 154
1812/154 = 11.766 ≈ 12
154 x 12 = 1848
The number to be added = 1848 - 1812
= 36
Note:
If you add 36 to 1812, you get 1848
1848 is divisible by 7, 11, and 14 because it is a multiple of 154 which is the LCM of the three numbers
1812/154 = 11.766 ≈ 12
154 x 12 = 1848
The number to be added = 1848 - 1812
= 36
Note:
If you add 36 to 1812, you get 1848
1848 is divisible by 7, 11, and 14 because it is a multiple of 154 which is the LCM of the three numbers
Answered by
0
Answer:
36
Step-by-step explanation:
To Find: what least value which should be added to 1812 to make it divisible by 7 11 and 14
Solution : The LCM of 7, 11 and 14 = 154
Now,
1812/154 = 11.766 ≈ 12
154 x 12 = 1848
The number to be added = 1848 - 1812
= 36
Now,If you add 36 to 1812, you get 1848
And 1848 is divisible by 7, 11, and 14 because it is a multiple of 154 which is the LCM of the three numbers
So, 36 is the least number which should be added to 1812 to make it divisible by 7 11 and 14
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