Math, asked by bikeshnarzary7765, 1 year ago

what least value which should be added to 1812 to make it divisible by 7 11 and 14

Answers

Answered by danielochich
11
The LCM of 7, 11 and 14 = 154


1812/154 = 11.766 ≈ 12


154 x 12 = 1848


The number to be added = 1848 - 1812

                                        = 36



Note:

If you add 36 to 1812, you get 1848


1848 is divisible by 7, 11, and 14 because it is a multiple of 154 which is the LCM of the three numbers
Answered by wifilethbridge
0

Answer:

36

Step-by-step explanation:

To Find: what least value which should be added to 1812 to make it divisible by 7 11 and 14

Solution : The LCM of 7, 11 and 14 = 154

Now,

1812/154 = 11.766 ≈ 12

154 x 12 = 1848

The number to be added = 1848 - 1812

                                            = 36

Now,If you add 36 to 1812, you get 1848

And 1848 is divisible by 7, 11, and 14 because it is a multiple of 154 which is the LCM of the three numbers

So, 36 is the least number which should be added to 1812 to make it divisible by 7 11 and 14


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