What length of German silver wire, diameter 0.050 cm, is needed to make a 28 resistor, if the resistivity of German silver is 2.2 x 10 -7 m?
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Given:
The resistor of resistance be 28 ohm
The diameter of silver wire is 0.050 cm
The resistivity of the german silver 2.2×10⁻⁷
To find:
The length of the german silver wire.
Solution:
Using the resistivity formula
R=ρl/A
We need to find the value of A
A=π(0.050)²
A=625π×10⁻²⁵
Putting above the values in the formula
l=RA/ρ
l=28×625π×10⁻³/2.2
l=24.98 m
l=25 m
So, the length of the german silve be 25 m
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