What length of tarapaulin 3 m wide will be required to make a conical tent of height 8 cm and base radius 6m ? Assume that the extra length of material that will be required?
Answers
Height ( h ) = 8m
Height ( h ) = 8mRadius ( r ) = 6m
Height ( h ) = 8mRadius ( r ) = 6mSo, its length = l2 = h2 + r2
Height ( h ) = 8mRadius ( r ) = 6mSo, its length = l2 = h2 + r2= l2 = ( 8 )2m + ( 6 )m2
Height ( h ) = 8mRadius ( r ) = 6mSo, its length = l2 = h2 + r2= l2 = ( 8 )2m + ( 6 )m2= l2 = 64m + 36m
Height ( h ) = 8mRadius ( r ) = 6mSo, its length = l2 = h2 + r2= l2 = ( 8 )2m + ( 6 )m2= l2 = 64m + 36m= l2 = 100m
Height ( h ) = 8mRadius ( r ) = 6mSo, its length = l2 = h2 + r2= l2 = ( 8 )2m + ( 6 )m2= l2 = 64m + 36m= l2 = 100m= l = 10m
Height ( h ) = 8mRadius ( r ) = 6mSo, its length = l2 = h2 + r2= l2 = ( 8 )2m + ( 6 )m2= l2 = 64m + 36m= l2 = 100m= l = 10mCurved surface area of the cone = TTrl
Height ( h ) = 8mRadius ( r ) = 6mSo, its length = l2 = h2 + r2= l2 = ( 8 )2m + ( 6 )m2= l2 = 64m + 36m= l2 = 100m= l = 10mCurved surface area of the cone = TTrl= 3.14 x 6m x 10m
Height ( h ) = 8mRadius ( r ) = 6mSo, its length = l2 = h2 + r2= l2 = ( 8 )2m + ( 6 )m2= l2 = 64m + 36m= l2 = 100m= l = 10mCurved surface area of the cone = TTrl= 3.14 x 6m x 10m= 188.4 cm2
Height ( h ) = 8mRadius ( r ) = 6mSo, its length = l2 = h2 + r2= l2 = ( 8 )2m + ( 6 )m2= l2 = 64m + 36m= l2 = 100m= l = 10mCurved surface area of the cone = TTrl= 3.14 x 6m x 10m= 188.4 cm2The extra length of material that will be required for stiching margins and wastages in cutting is approx 20 cm = 0.2m
Height ( h ) = 8mRadius ( r ) = 6mSo, its length = l2 = h2 + r2= l2 = ( 8 )2m + ( 6 )m2= l2 = 64m + 36m= l2 = 100m= l = 10mCurved surface area of the cone = TTrl= 3.14 x 6m x 10m= 188.4 cm2The extra length of material that will be required for stiching margins and wastages in cutting is approx 20 cm = 0.2mSo, its length = l - 0.2m
Height ( h ) = 8mRadius ( r ) = 6mSo, its length = l2 = h2 + r2= l2 = ( 8 )2m + ( 6 )m2= l2 = 64m + 36m= l2 = 100m= l = 10mCurved surface area of the cone = TTrl= 3.14 x 6m x 10m= 188.4 cm2The extra length of material that will be required for stiching margins and wastages in cutting is approx 20 cm = 0.2mSo, its length = l - 0.2mand its width = 3m
Height ( h ) = 8mRadius ( r ) = 6mSo, its length = l2 = h2 + r2= l2 = ( 8 )2m + ( 6 )m2= l2 = 64m + 36m= l2 = 100m= l = 10mCurved surface area of the cone = TTrl= 3.14 x 6m x 10m= 188.4 cm2The extra length of material that will be required for stiching margins and wastages in cutting is approx 20 cm = 0.2mSo, its length = l - 0.2mand its width = 3marea of sheet = CSA of tent
Height ( h ) = 8mRadius ( r ) = 6mSo, its length = l2 = h2 + r2= l2 = ( 8 )2m + ( 6 )m2= l2 = 64m + 36m= l2 = 100m= l = 10mCurved surface area of the cone = TTrl= 3.14 x 6m x 10m= 188.4 cm2The extra length of material that will be required for stiching margins and wastages in cutting is approx 20 cm = 0.2mSo, its length = l - 0.2mand its width = 3marea of sheet = CSA of tentso the area of the trapaulln = l x b
Height ( h ) = 8mRadius ( r ) = 6mSo, its length = l2 = h2 + r2= l2 = ( 8 )2m + ( 6 )m2= l2 = 64m + 36m= l2 = 100m= l = 10mCurved surface area of the cone = TTrl= 3.14 x 6m x 10m= 188.4 cm2The extra length of material that will be required for stiching margins and wastages in cutting is approx 20 cm = 0.2mSo, its length = l - 0.2mand its width = 3marea of sheet = CSA of tentso the area of the trapaulln = l x b= ( l - 0.2m ) x 3m = 188.4m2
Height ( h ) = 8mRadius ( r ) = 6mSo, its length = l2 = h2 + r2= l2 = ( 8 )2m + ( 6 )m2= l2 = 64m + 36m= l2 = 100m= l = 10mCurved surface area of the cone = TTrl= 3.14 x 6m x 10m= 188.4 cm2The extra length of material that will be required for stiching margins and wastages in cutting is approx 20 cm = 0.2mSo, its length = l - 0.2mand its width = 3marea of sheet = CSA of tentso the area of the trapaulln = l x b= ( l - 0.2m ) x 3m = 188.4m2= l - 0.2m = 62.8m2
Height ( h ) = 8mRadius ( r ) = 6mSo, its length = l2 = h2 + r2= l2 = ( 8 )2m + ( 6 )m2= l2 = 64m + 36m= l2 = 100m= l = 10mCurved surface area of the cone = TTrl= 3.14 x 6m x 10m= 188.4 cm2The extra length of material that will be required for stiching margins and wastages in cutting is approx 20 cm = 0.2mSo, its length = l - 0.2mand its width = 3marea of sheet = CSA of tentso the area of the trapaulln = l x b= ( l - 0.2m ) x 3m = 188.4m2= l - 0.2m = 62.8m2= l = 63m
Height ( h ) = 8mRadius ( r ) = 6mSo, its length = l2 = h2 + r2= l2 = ( 8 )2m + ( 6 )m2= l2 = 64m + 36m= l2 = 100m= l = 10mCurved surface area of the cone = TTrl= 3.14 x 6m x 10m= 188.4 cm2The extra length of material that will be required for stiching margins and wastages in cutting is approx 20 cm = 0.2mSo, its length = l - 0.2mand its width = 3marea of sheet = CSA of tentso the area of the trapaulln = l x b= ( l - 0.2m ) x 3m = 188.4m2= l - 0.2m = 62.8m2= l = 63mTherefore, length of the trapaulin sheet required is 63m.