Question

What length of tarpaulin 3 m wide will be required to make conical tent of height 8m and base radius 6m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20cm.(use π=3.14)​

Answer 1

Answer:

Answer:Given: Height (h) = 8m

Radius (r) = 6m

According to Pythagoras theorem,

l² = r² + h²

l² = 6²+ 8²

l² = 36 + 64

l² = 100

l = √100 = 10 m

Therefore, slant height of the conical tent = 10 m.

CSA of conical tent = πrl

= π × 6m × 10m

= 3.14 × 6m × 10m

= 188.4 m2

Now, Let the length of tarpaulin sheet required be "x" m

As 20 cm will be wasted, therefore, the effective length will be = (x − 20 cm) = (x − 0.2 m)

Breadth of tarpaulin = 3 m

Area of sheet = CSA of tent

⇒ [(x − 0.2 m) × 3] m = 188.4 m²

⇒ x − 0.2 m = 62.8 m

⇒x = 63 m

Therefore, the length of the required tarpaulin sheet will be 63 m.

Answer 2

Answer:

11.46 is the answer

Step-by-step explanation:

ar(tarpaulin)=LSA(cone)

for Cone (tent),

r=6

h=8

l=$\sqrt{h^{2}}+r^{2}$

=√(8)²+(6)²

=√64+36

=√120

=10.95

LSA(cone)=πrl

               =3.14×10.95×6

               =34.38

from the first statement,

ar(rectangle)=34.38m

Length × Breadth=34.38m

l×3=34.38m

l=34.38÷3

l=11.45m

Therefore the length of tarpaulin required is 11.45m