Question

What length of tarpaulin 3 m wide will be required to make conical tent of height & m and base radius 6 m? Assume that the extra length of material that will be required to (11) cost of the canvas required to make the tent, if the cost of 1 m canvas is Rs 70. stitching margins and wastage in cutting is approximately 20 cm (Use 3.15).​

Answer 1

Answer:

63m

Step-by-step explanation:

Given a conical tent with

Height ( h ) = 8m

Radius ( r ) = 6m

So, its length = l²= h² + r²

= l²= ( 8 )2m + ( 6 )m2

= l²= 64m + 36m

= l²= 100m

= l = 10m

Curved surface area of the cone = TTrl

= 3.14 x 6m x 10m

= 188.4 cm²

The extra length of material that will be required for stiching margins and wastages in cutting is approx 20 cm = 0.2m

So, its length = l - 0.2m

and its width = 3m

area of sheet = CSA of tent

so the area of the trapaulln = l x b

= ( l - 0.2m ) x 3m = 188.4m²

= l - 0.2m = 62.8m²

= l = 63m

Therefore, length of the trapaulin sheet required is 63m.