Question

What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m ? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm.
( use pi =3.14 )​

Answer 1

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

☃ ƛƝƧƜЄƦ ☃

$\small \red{{Slant \: height \: of \: the \: tent \: = \sqrt{(6)^{2} + (8) ^{2}} \: m = \sqrt{36 + 64 }m = 10 \: m }} \\ \\ \small \blue{{Area \: of \: tarpaulin \: required = \: \pi \: r \: l \: = 3.14 \times 6 \times 10 \: m^{2} }} \\ \\ \small \green{{ = 188.4 \: m^{2}}}\\ \\ \ \small \pink{{ \therefore \: Length \: of \: tarpaulin \: required \: = \frac{188.4}{3} = 62.8 \: m }} \\ \\ \small \orange {{Total \: length \: required \: including \: wastage = (62.8 + 0.2 )m = 63 \: m. }}$

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━