Question

What length of tarpaulin 3m wide will be required to make conical tent of height 8 m and base radius 6m ? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm (use π = 3.14).​

Answer 1

Answer:

ANSWER

h = Height of tent = 8 m

r = Base radius = 6 m

Therefore,

l= r 2 +h 2=10 m

Curved surface area of the cone = πrl=3.14×6×10 m

2

Therefore, length of 3 m wide tarpaulin required =

3

3.14×6×10

=62.8 m

Extra length required = 0.2 m

Therefore, total length required = 63 m

Answer 2

Answer:

Height if tent (h) : 8m

Radius of its Base ( r ) : 6m

l =

$= \sqrt{ {r}^{2} + {h}^{2} }$

$= \sqrt{ {6}^{2} + {8}^{2} }$

$= \sqrt{36 + 64} = \sqrt{100 }$

= 10m

Curved Surface Area : πrl

= 3.14 x 6 x 10

= 188.4cm²

Length of 3m wide tarpaulin required=

$= \frac{3.14 \times 6 \times 10}{3}$

= 62.8m

Extra length Required = 20cm = 0.2m

Total length Required = 62.8 + 0.2

= 63 m

$ans$