What length of tarpaulin 3m wide will be required to make conical tent of height 1 metre and base radius 6m assuming that the extra length of material that would be required for stitching margins and wastage in cutting is approximately 20 cm take pi 3.14?
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Q: What length of tarpaulin 3 m wide will be required to make conical tent of height 8 metre and base radius 6 m assuming that the extra length of material that would be required for stitching margins and wastage in cutting is approximately 20 cm.
Solution :-
Given : Breadth of tarpaulin = 3 m
Find the length of the tarpaulin to make conical tent of height 8 m and base radius 6 m :
Slant height (l) = √(h² + r²)
= √(8² + 6²)
= √(64 + 36)
= √100 = 10
Here,
Area of tarpaulin = Curved surface area of tent
=> (Length × Breadth) = πrl
=> Length = (22 × 6 × 10)/(3 × 7) = 62.8
Total length = Length + Margin
= 62.8 + 0.2
= 63 m
Hence,
Length of tarpaulin = 63 m
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