What length of trapaulin 3 m wide will be required to make conical tent of height 8 m and and base radius 6m? assume that the extra length of material that will be required for stiching margins and wastage in cutting is approximately 20 cm.
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12
HEY!!
Given, height of conical tent = 8 m
and radius of tent = 6 m
Now, slant height of tent
∴ Curved surface area of tent =
Given, breadth of tarpaulin sheet = 3 m
Let the length of tarpaulin sheet required will be equal to x m.
It is given that 20 cm (or 0.2 m) length of material is wasted in stitching margins and cutting.
∴ effective length of tarpaulin sheet = (x - 0.2) m
It is quite clear that, area of sheet = curved surface area of tent
⇒(x- 0.2) × 3 = 188.4
⇒(x- 0.2) = 62.8
⇒x = 62.8 + 0.2 = 63 m
Hence, the tarpaulin sheet of 63 m length will be required to make conical height of given dimensions.
Given, height of conical tent = 8 m
and radius of tent = 6 m
Now, slant height of tent
∴ Curved surface area of tent =
Given, breadth of tarpaulin sheet = 3 m
Let the length of tarpaulin sheet required will be equal to x m.
It is given that 20 cm (or 0.2 m) length of material is wasted in stitching margins and cutting.
∴ effective length of tarpaulin sheet = (x - 0.2) m
It is quite clear that, area of sheet = curved surface area of tent
⇒(x- 0.2) × 3 = 188.4
⇒(x- 0.2) = 62.8
⇒x = 62.8 + 0.2 = 63 m
Hence, the tarpaulin sheet of 63 m length will be required to make conical height of given dimensions.
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