what length of trapaulin 3m wide will be required to make conical tent of height 8m and base radius 6m ? assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20cm (use π=3.14).
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h = Height of tent = 8 m
r = Base radius = 6 m
Therefore,
l= √r² +h² =10 m
Curved surface area of the cone = πrl=3.14×6×10² m
Therefore, length of 3 m wide tarpaulin required = 3.14×6×10 / 3 =62.8 m
Extra length required = 0.2 m
Therefore, total length required = 63 m
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