Question

What lingth of tarpaulin 3m weide will be
required to make conical text of height 8m
and are radice 6m? Assume that the
extra length of material that will be required
for stitching margins and waited wealtage​

Answer 1

Answer:

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Answer 2

$Answer⤵️$

h = Height of tent = 8m

r = Base radius = 6 m

Therefore,

$1 = \sqrt{ {r}^{2} + {h}^{2} } = 10m$

curved surface area of the cone =

$\pi \: rl \: = 3.14 \times 6 \times 10 {m}^{2}$

Therefore,length of 3m wide tarpaulin required

$= \frac{3.14 \times 6 \times 10}{3} = 62.8$

Extra length required = 0.2

Therefore,Total length required = 63m