What magnitude charge creates a 1.0 N per C electric field at a point 1.0 m away?
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F = KQ/ r2
therefore 1 = 9×10^9 Q
Q= 1.11 × 10^(-10) C
therefore 1 = 9×10^9 Q
Q= 1.11 × 10^(-10) C
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There are a couple of potential outcomes.
To start with, if the charge q is very still in the electric field E and attractive field B, at that point just the electric field applies a power in light of the fact that the charge must move for the attractive field to apply a power.
The Coulomb is a 'determined' unit relying upon the fundamental units of the metric framework.
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