Question

What magnitude point charge creates a 10,000 N/C electric field at a distance of 0.250 m? How large is the field at 10.0 m?​

Answer 1

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Answer :

E_2 = 6.25 N/C

Explanation :

The relation between Electric Field and distance is $\frac{E_1}{E_2}= \frac{r_2^2}{r_1^2}$

Given , $E_1=10,000 N/C , r_1=0.250 m, E_2=? N/C,r_2=10m$

$=>\frac{10,000}{E_2} =\frac{10^2}{0.25^2}\\\\ =>\frac{10,000}{E_2}=40^2\\\\=>E_2=\frac{10,000}{1600} \\\\=>E_2=6.25N/C$

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