Question

What magnitude point charge creates a 10,000 n/c electric field at a distance of 0.250 m?

Answer 1

Since,  
     E=kQ/r^2
=> 10^4 = 9*(10^9)*Q / (0.25)^2
=> (10^4) * (0.25^2) / 9*(10^9) = Q
=> 0.00694 * 10^(-5) = Q
=> 6.94 * 10(-8) Coulombs = Q

Answer 2

Given:

E = 10,000n/c

Distance = 0.250m

To Find:

Magnitude point

Solution:

     E = kQ/r²

⇒ $10^{4} = 9(10^{9}^{Q}/(0.25)^{2}$

⇒ ($10^{4} * 0.25^{2}/9(10^{9})=Q$

⇒ 0.00694× $10^{-5}$=Q

⇒ 6.94 × 10(-8) Coulombs = Q