Question

What makes the pi bonds of so42- if all Ps involved in hybridization

Answer 1

Explanation:

(A) S atom has 4 bonding domains and zero lone pairs of electrons. Hence it is sp

3

hybridized with tetrahedral geometry and bond angles of 109.5

o

(B) All the S−O bond length are equal, and shorter than expected. This is due to delocalization of electrons (resonance).

(C) It contains four σ-bonds between the S and the O atoms, two π-bonds delocalized over the S and the four O atoms, and all the S−O bonds have a bond order of 1.5. Thus each S−O bond has partial double bond character.

(D) Oxidation state of sulphur is +6 and all oxygen atoms have −2 oxidation states.

+6+4(−2)=−2