what mass of 0.5 molal urea solution contains 0.15 mole urea
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Answered by
4
Molality of a solution is calculated in the following way:
molality = moles of solute/ kg of solvent
Therefore mass of solvent =molality/moles
Molality = 0.5 molal
Moles = 0.15 moles
Thus, mass = 0.5/0.15
= 3.33 kg
Therefore the mass of 0.5 molal urea that contains 0.15 moles is 3.33 kg urea
molality = moles of solute/ kg of solvent
Therefore mass of solvent =molality/moles
Molality = 0.5 molal
Moles = 0.15 moles
Thus, mass = 0.5/0.15
= 3.33 kg
Therefore the mass of 0.5 molal urea that contains 0.15 moles is 3.33 kg urea
Answered by
0
it's 309gram .
9g of urea in 0.15 mole of ureA +mass solvent of 0.5 molal solution having .0.15 mole urea which if 300 .
300 + 9 =309.
hope this will help you ..
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