Question

What mass of 60% of caco3 is required to react with 50gm of hcl

Answer 1

Answer:

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Explanation:

Equation of the reaction between calcium carbonate and hydrochloric acid

2HCl (l) + CaCO3 (s) → CaCl2 (aq) + H2O (l) + CO2 (g)

The molar mass of CaCO3 is 100 g/mol. Thus the amount of 50g of CaCO3 is 0.5 mol.

One mol of calcium carbonate reacts with two mol of hydrochloric acid. Thus, 0.5 mol of CaCO3 reacts with 1 mol of HCl.

The molar mass of HCl is 36.5 g/mol. The mass of 1 mol HCl is 36.5 g.

The concentration of HCl in the solution by weight is

w(HCl) = m(HCl) / m(solution)

Thus, the mass of the 20% solution of 36.5 g of HCl is

m(HCl solution) = m(HCl) / w(HCl) = 36.5 g / 0.2 = 182.5 g.

Answer: (iv) 182.5 g

50g CaCO3 will react with 182.5 g of 20% HCl by weight.

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