Question

what mass of 90% pure caco3 is required to neutralize 2 litre decinormal solution of HCL​

Answer 1

Answer:

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Explanation:

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Answer 2

HERE IS UR ANSWER

Explanation:

CaCO3 + 2HCl ===> CaCl2 +CO2+H2O .

So 2000 ml.of 1N HCl neutralises = 1 mole of CaCO3= 100 g of pure CaCO3.

So 2000 ml.of 0.1 N HCl will neutralise=100 x 0.1= 10 g of pure CaCO3.

Since CaCO3 is only 90% pure the mass of 90% pure CaCO3 required = 10/0.9= 11.11 g