Question

What mass of agcl is produced by mixing 50.0ml of 1.00 m agno3 with 50.0ml of 1.00 nacl

Answer 1

Given:

• Molarity of AgNO₃ (M1) = 1 M
• Molarity of NaCl (M2) = 1 M
• Volume of AgNO₃ (V1) = 50 mL = 0.05 L
• Volume of NaCl (V2) = 50 mL = 0.05 L
• Molar mass of AgCl (Mm) = 143.5 g/mol

To find:

The mass of AgCl produced.

Solution:

• Moles of AgNO₃ (n1) = M1*V1(in L) = 0.05
• Moles of NaCl (n2) = M2*V2(in L) = 0.05
• One mole of AgNO₃ reacts with one mole of NaCl to produce one mole of AgCl.
• Moles of AgCl produced (n) = 0.05
• Mass of AgCl produced = n*Mm = 0.05*143.5 = 7.175 g

Answer:

The mass of AgCl produced = 7.175 g