Question

what mass of AgNo3 must be dissloved in 200 g of water to prepare a 0.250m solution.
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Answer 1

Answer:

8.5gm

Explanation:

As we know,molality(m)=no. Of moles of solute/mass of solvent in gm ×1000

Molecular mass of AgNO3 =170u

Given,m =0.250

Mass of solvent(water)=200g

Let mass of AgNO3 needed =x

Moles=mass in gm./molecular mass

Therefore, x/ ×1000

170----------=.250

200

On solving,

X=8.5gm..........

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