Question

What mass of Al2O3is produced from 14.5g ofAl metal when it reacts completely with oxygen according to following equation. 4Al+3O2. 2Al2O3

Answer 1

Explanation:

here is your answer .....

Answer 2

Answer:

2 mol Al2O3 4 mol A1 = 0.56335 mol Al,SO3

Multiply mol Al,03 by its molar mass (101.961 g/mol).

0.56335 mol Al03 x

= 101.91g Al,03 1 mol ALO3

57.4 g Al,03 (rounded to three significant figures)

30.4 g Al will produce 57.4 g Al,O3

Mass of aluminum oxide produced by 30.4 g

oxygen gas

We can put all three steps into one equation.

1 mol O2

30.4go,

2 mol AbO3

64.6 g A1,03

31.998 g 0, 3 mol O2 101.961g Al2O3 = 1 mol Al2O3 (rounded to three significant figures)

30.4 g O, will produce 64.6 g Al2O3.

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