Question

what mass of ca will contain the same number of atoms as are present in 3.2 g of s?

Answer 1

gmm of sulphur=32gram
1 mole sulphur=6.023*10^23 atoms(in 32 gram sulphur)
3.2 gram sulphur would contain= 6.023*10^23 *3.2/32= 6.023*10^22

gmm of calcium=40g
1mole of calcium= (40g)
mass of 6.023*10^22 calcium = 40*6.023*10^22/6.023*10^23= 4 grams