Chemistry, asked by nikitaparuvada999, 10 months ago

What mass of CaCO3 would react with HCl to produce 5.6 L CO2 at STP along with CaCl2 and H2O ?

Answers

Answered by kanukanchan36
2

Answer:

25 gm CaCO3

Explanation:

CaCO3+2HCl > CaCl2+CO2+H2O

This reaction, we get,

STP

22.4 L CO2 = 100 gm CaCO3

5.6 L CO2= (100×5.6) /22.4 gm CaCO3

= 25 gm CaCO3

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