What mass of CaCO3 would react with HCl to produce 5.6 L CO2 at STP along with CaCl2 and H2O ?
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Answer:
25 gm CaCO3
Explanation:
CaCO3+2HCl > CaCl2+CO2+H2O
This reaction, we get,
STP
22.4 L CO2 = 100 gm CaCO3
5.6 L CO2= (100×5.6) /22.4 gm CaCO3
= 25 gm CaCO3
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