Chemistry, asked by avingaur, 1 year ago

What mass of calcium chloride in grams would be enough to produce 14.35g of Agcl ?

Answers

Answered by nagathegenius
0

Answer:

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Explanation:

equivalent of calcium chloride =  equivalent of 14.32 agcl

molarity*f=14.32/143.5*f

molarity*2=1/10

molarity=1/20

w/111=1/20

w=5.55gm

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