What mass of calcium chloride in grams would
be enough to produce 14.35 gm of AgCl.
(At. mass Ca = 40, Ag = 108) -
(1) 5.55 gm
(2) 8.295 gm
(3) 16.59 gm
(4) 11.19 gm
Answers
Answered by
1
Answer:
CaCl
2
+2Ag→2AgCl+2Ca
Equivalent of CaCl
2
= Equivalent of AgCl
∴
111
w×2
=
143.5
14.35
[E
w
=
2
Mw
]
w=5.55g.
Answered by
1
Explanation:
3)16.59gm and please don't forget to follow me please.
Similar questions