What mass of calcium oxide be obtained by heating 5 moles of calcium carbonate?
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Hey.
Here is your answer.
The balanced equation for the decomposition of calcium carbonate is as follows:
CaCO3 ---(heat)----> CaO + CO2
As 1 mole of Caclium carbonate on decomposition yields only 1 mole of CaO therefore,
5 mole of CaCO3 will also form 5 mole of CaO.
We known,
Number of moles = Mass/ Molar mass
Molar mass of CaO = 56.0 g per mole
Mass of CaO = 56.0 x 5
= 280g
Hence, 280g of CaO will be obtained by the decomposition of 5 mol of CaCO3.
Thanks.
Here is your answer.
The balanced equation for the decomposition of calcium carbonate is as follows:
CaCO3 ---(heat)----> CaO + CO2
As 1 mole of Caclium carbonate on decomposition yields only 1 mole of CaO therefore,
5 mole of CaCO3 will also form 5 mole of CaO.
We known,
Number of moles = Mass/ Molar mass
Molar mass of CaO = 56.0 g per mole
Mass of CaO = 56.0 x 5
= 280g
Hence, 280g of CaO will be obtained by the decomposition of 5 mol of CaCO3.
Thanks.
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