Question

What mass of calcium will contain the same number of atoms as are present in 3.2 g sulphur?

Answer 1

Answer:

Gmm of sulphur=32gram

1 mole sulphur=6.023*10^23 atoms(in 32 gram sulphur)

3.2 gram sulphur would contain= 6.023*10^23 *3.2/32= 6.023*10^22

gmm of calcium=40g

1mole of calcium= (40g)

mass of 6.023*10^22 calcium = 40*6.023*10^22/6.023*10^23= 4 grams