Question

What mass of carbon dioxide (CO2) will contain 3.011x1023 molecules?​

Answer 1

Answer:

3.011×10

23

no. of nitrogen atom at mass of nitrogen =14g

1 mole of nitrogen contains 6.022×10

23

atoms

14g will contains 6.022×10

23

atoms

how,

6.022×10

23

14

g contains 1 atom

∴(

6.022×10

23

14

)×3.011×10

23

=

2

14

=7g of N.

Explanation:

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Answer 2

Answer:

Explanation:

of mole=no.of the molecules/Avogadro no.

n=no.of mole

n=3.011*10^23/6.022*10^2

n=0.5 mole

no.of mole.=mass/molecular mass

molecular mass of CO2=C-12g;O2-16*2-32=12+32g=44g

m(mass)=0.5mole*44g=22g