Question

What mass of cerussite, PbCO3, would contain 35.0 grams of lead?(Pb=207, C=12, O=16) *

27.1 g
35.2 g
42.4 g
51.7 g
45.1 g

Answer 1

Answer:

The mass of cerussite, $PbCO_{3}$ that contain $35.0\ g$ of lead is $45.1\ g.$

Explanation:

The molar mass of cerussite, $PbCO_{3}$  is  $267g.$

Given, the mass of Pb as $207g.$

From the formula of cerussite, it is understood that,

    $207g$ of Pb is present in $267g$ of $PbCO_{3}.$

So,

     $35.0g$ of Pb is present in $\frac{35\ *\ 267}{207}$ g of $PbCO_{3}.$

⇒  which is equal to  $45.1\ g$ of $PbCO_{3}.$

Hence the mass of $PbCO_{3}$ that contain $35.0\ g$ of lead is $45.1\ g.$

Answer 2

The mass of cerussite is 45.14 grams.

Given: PbCO3 contain 35.0 grams of lead.

To find: We have to find the mass of cerussite.

Solution:

The atomic mass of Pb is 207.

The atomic mass of C is 12 and Oxygen is 16.

The molecular weight of cerussite is-

$207 + 12 + 16 \times 3 = 267$

207 gram of lead is present in 267-gram cerussite.

35 grams of lead is present in

$\frac{267 \times 35}{207} = 45.14$

Thus the mass of cerussite is 45.14 grams.