what mass of CH4 taken whuch contain 2.4 ×10^24 atom hydrogen
plz its improtant
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Answered by
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The statement must be as ‘2.4*10^-23’ atoms of hydrogen.
1 mole CH4 weighs=16 g
% of H2 in CH4=4/16*100=25%
1 mole of H2 weighs=2 g
6.022*10^23 atoms of H2 weigh=2 g
1 atom of H2 weighs=2/6.022*10^23
2.4*10^-23 of H2 weigh=2/6.022*10^23*(2.4*10^-23)=0.80 g
Therefore 25% of weight of CH4=0.80
1/4 of weight=4/5
Weight=4/5*4=3.2 g
Answered by
0
Answer:
The statement must be as ‘2.4*10^-23’ atoms of hydrogen.
1 mole CH4 weighs=16 g
% of H2 in CH4=4/16*100=25%
1 mole of H2 weighs=2 g
6.022*10^23 atoms of H2 weigh=2 g
1 atom of H2 weighs=2/6.022*10^23
2.4*10^-23 of H2 weigh=2/6.022*10^23*(2.4*10^-23)=0.80 g
Therefore 25% of weight of CH4=0.80
1/4 of weight=4/5
Weight=4/5*4=3.2 g
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