What mass of chlorine gas would be required to produce 0.015kg of phosphorus pentachloride?
Answers
2 PH3 + 8 CL2 = 2 PCL5 + 6 HCL
M(Cl2) = 71 g/mol
M(PCL5) = 208.24 g/mol
M(PH3) = 40.0 g/mol
From the equation :
568 g (CL2) = 416.48 g (PCL5)
x g (Cl2) = 15 g (PCL5)
x = 568*15/416.48 = 20.46 g (CL2)
From the equation we can see, that PH3 is an excess. So the calculations are carried out on chlorine.
Phosphorus pentachloride is produced by the reaction between phosphine and chlorine gas.
The required chemical equation is :
2PH₃ +8Cl₂ ---->2PCl5 + 6HCl
its clear that 2 moles of Phosphine reacts with 8 moles of chlorine to give 2 moles of phosphorous penta chloride and 6 moles of hydrochloric acid.
molecular mass of chlorine = Cl2= [ 2x 35.5] =71 u
Molecular mass of PCl5 = [ 31+ 5x35.5]= [ 31+177.5]=208.5 u
568 g of chlorine gives 417g of PCl5
? ------------? 0.015KG (15g)
= 568x 15/417
=8520/417
=20.43 g
∴ 20.43 g of chlorine gas is required to produce 0.015kg of phosphorus pentachloride