Question

What mass of copper can be produced by the electrolysis of a cuso3 solution for 1 hour with a steady current of 100 ampere?

Answer 1

m=I⋅tF⋅Mzm=I⋅tF⋅Mz

There M=64g/molM=64g/mol for copper, z=2z=2,

because copper was in +2+2 oxidation state,

F=96485C/molF=96485C/mol - the Faraday constant.

The current and time are presented in your question.

Good luck with a simple math! :)

P.S.:

Of course, the real mass will be less, because it depends on electrolysis conditions.