What mass of copper (specific heat capacity 0.385Jg) can be heated through the same temperature difference when supplied with the same amount of energy as above.
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q=m×c×∆T
C=0.385Jg/k
Q=1000.0J
m=10.0g
∆T=?
∆T= 1000J/10.0 ×0.385Jg/k
=259.7k =260K =260°C
C=0.385Jg/k
Q=1000.0J
m=10.0g
∆T=?
∆T= 1000J/10.0 ×0.385Jg/k
=259.7k =260K =260°C
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