Question

what mass of each element is present in 1.5 mole of na2so4 sodium sulphate​

Answer 1

Answer: 189

Explanation: Sodium sulphite (Na2so3)

No.of moles= mass/molar mass

1.5 = mass/ 126

Mass = 126×1.5 = 189 answer this will be total mass

Now to calculate mass of each element u can simply apply mole concept here

For Na2

No.of moles = mass / molar mass

1.5 = mass / 46

Mass = 46×1.5

= 69

For sulphur

1.5= mass/32

Mass =48

Answer 2

Answer:

Molar mass of Na2SO4 = [(2 × 23.0) + (32.00) + 4 (16.00)] = 142 g

Mass percent of an element = (Mass of that element in compound/Molar mass of that compound) × 100

∴ Mass percent of sodium (Na): (46/142) × 100 = 32.39%

Mass percent of sulphur(S): (32/142) × 100 = 22.54%

Mass percent of oxygen:(O): (64/142) × 100 = 45.07%