Question

what mass of glucose (in grams) is added to 72 g of water which lower vapour pressure by 2%?

Answer 1

Answer:

H2NCONH2)→M=60g/mol

m= molar mass

MC6H12O6=12×6+12×1+6×6=72+12+96+180g/mol

Relative lowering in Vapour pressure=no.ofmoles×massofwatermolarmassofsolvent=0.33×5018

180W×10018=601×5018W=6g

Hope it helps

Answer 2

Answer:

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