Question

What mass of HCl is present in 0.80 molar, 2500ml solution?

Answer 1

Answer:

73 gram

Explanation:

Number of milimoles of HCl = 0.8*2500 = 2000 milimoles = 2 moles

Mass of HCl present = 2 * Molar Mass of HCl = 2 * 36.5 = 73 gram

Answer 2

Dear Student,

◆ Answer -

W = 73 g

● Explanation -

# Given -

M = 36.5 g/mol

V = 2500 ml = 2.5 L

m = 0.8 molar

# Solution -

Concentration of the solution is calculated as -

Molarity = moles of solute / volume of solution

m = (W/M) / V

0.80 = (W/36.5) / 2.5

W = 0.80 × 2.5 × 36.5

W = 2 × 36.5

W = 73 g

Hence, 73 g of HCl is present in given solution.

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