Question

What mass of hi should be present in 0.250 l of solution to obtain a solution with each ph value 2.85?

Answer 1

pH = 1.30  

[H+]= 10^-1.30 = 0.050  

HI is a strong acid so [HI] = 0.050 M  

Moles HI = 0.050 x 0.250 =0.0125  

Moles HI = 127.9 g/mol x 0.0125 mol = 1.60 g