Question

What mass of hi should be present in 0.250 l of solution to obtain a solution with each ph value?

Answer 1

Answer

pH = 1.30

[H+]= 10%-1.30 = 0.050

Hl is a strong acid so [HI] = 0.050 M

Moles HI = 0.050 x 0.250 =0.0125

—_

Moles HI = 127.9 g/mol x 0.0125 mol

=

1.60 g

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Answer 2

Explanation:

1.30 os pH value of the solution