Question

What mass of hydrogen chloride is necessary to neutralize a 75.1⋅g mass of calcium hydroxide?

Answer 1

Hydrogen chloride or HCl is a strong acid . As having a acidic nature it has a property to neutralize strong base calcium hydroxide Ca(OH)²

Answer 2

Answer:

Approx.  74g

Step-Step solution:

We need (i) a stoichiometric equation:

Ca(OH)2(s)+2HCl(aq)→CaCl2(aq)  +2H2O(l)

And (ii), equivalent quantities of calcium hydroxide:

Moles of calcium hydroxide

=7.51 g/ 74.09 g mol -1 = 1.01 mol

And for an equivalent quantity of hydrochloric acid, we thus need

2×1.01 mol×36.46 g mol ⁻¹= 73.6 g

Why did I double the molar quantity of calcium hydroxide?

Given that we would normally use  34% conc. hydrochloric acid,  which has an approx. molarity of  10.9 mol L⁻¹  , what is the volume of hydrochloric acid required for equivalence?