What mass of iodine is liberated from a solution of potassium iodine when 1 litre of chlorine gats at 10 degree celcius and 750 mm pressure is passed through it
Answers
Answer:
We can calculate the amount of iodine from the following procedure:-
1) First calculate the number of moles of KI from the given data using ideal gas equation
PV= nRT
where P= pressure, V= volume, n = number of moles, R= gas constant, T= temperature
Given: P= 750 mm Hg
since 760mm Hg= 1 atm
therefore 750mm Hg= 0.9868 atm
V= 1 L
R= 0.082 L atm mol-1 K-1
T= 10oC = 283K
putting all these values in ideal gas equation, we have
0.9868 × 1= n × 0.082 × 283
n= 0.042 mol
2) now, according to the equation, 1mole of KI react with 1 mole of Cl2 to form 1 mole of I2.
so 0.042 mole of KI will react with 0.042 mole of Cl2 to form 0.042 mole of I2.
3) To get the amount of I2 produced we have to multiply the number of moles with its molar mass.
so, 0.042 × 253.81= 10.793 g
Therefore 10.793 g of Iodine is formed
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