Question

what mass of kclo3 on heating gives sufficient o2 gas to completely burn 8 gm of sulphur

Answer 1

Here is the answer---

Reaction of the Decomposition of Potassium Chlorate →

2KClO₃ ----→ 2KCl +3O₂ 

Reaction of Aluminium with Oxygen →

4Al + 3O₂ ---→ 2Al₂O₃

Now,

From the Second Reaction,

 ∵ 4 moles of Aluminum Requires 3 moles of Oxygen.

∴ 1 moles of Aluminum requires 3/4 moles of Oxygen.

Now, 

From the First Equation,

∵ 3 moles of Oxygen is produced by the 2 moles of Potassium Chlorate.

∴ 1 moles of Oxygen is Produced by the 2/3 moles of KClO₃.

∴ 3/4 moles of O₂ is produced by the (2/3) × (3/4) moles of KClO₃.

   = 1/2 moles of KClO₃.

  = 0.5 moles of KClO₃.

∴ Moles of KClO₃ Required is 0.5 moles.

Answer 2

Explanation:

The condition which is required to complete this reaction in in the sunlight

and the type of reaction is decomposition or also done by displacement reaction..

The KCLO3 required 0.5 mole which is already solve by up .