Question

What mass of KX (Mm= 160 g/mol) is required to prepare 344 mL of a pH = 12.28 solution? The pKa of HX is 12.79

Answer 1

Given:

• The molar mass of KX (Mm) is equal to 160g/mol
• The volume of the solution(v) is equal to 344 mL
• The pH of the solution is 12.28.
• The pKa of HX is 12.79
• The pKw of water at room temperature is 14

To find:

The mass  of KX required.

Solution:

• KX is a salt of strong base and weak acid.
• Let C be the concentration of KX
• For KX, pH = (pKw + pKa -logC)/2 ⇒ logC = 2pH-pKw-pKa ⇒               C =5.88*10⁻³M
• Let w be the mass of KX required.
• So, C = (w*1000)/(Mm*v) ⇒ w = C×Mm×v/1000 ⇒ 0.323 g

Answer:

The mass of KX required is equal to 0.323g

Answer 2

Answer:

What mass of KX (Mm= 160 g/mol) is required to prepare 344 mL of a pH = 12.28 solution? The pKa of HX is 12.79. 1. See answer.

1 vote

Given:The molar mass of KX (Mm) is equal to 160g/molThe volume of the solution(v) is equal to 344 mLThe pH of the solution is 12.28.The pKa of HX is ... More

Imagewww.chegg.com › homework-help

Solved: What Mass Of KX (Mm= 160 G/mol) Is Required To Pre... | Chegg ...

Answer to What mass of KX (Mm= 160 g/mol) is required to prepare 344 mL of

Explanation:

follow me on my way home and the other side of the other side of the year old girl I have to be in the time as I Havehaveeyeyeyeyeyeheheh Hehhrhrhh heheh h